Can one possibly use the associative property of kernels in order to work out a so-called "triple" convolution?

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I am technically starting calculus next year but I've already started reading into it. So after finishing the Laplace transform section of Differential Equations on Khan Academy, I asked myself:

Considering the fact that the convolution transform is only defined for f(t) and g(τ), could one possibly work out say, f∗g∗h by finding the convolution (f∗g) and then evaluating its convolution together with, say, h(τ)?

I am asking this because I wanted to make a video on a so-called "triple" convolution, i.e. the convolution of 3 functions altogether. I am sorry if this statement seems obviously right / obviously wrong to you all, but please just remember that I am only just beginning to wrap my head around this stuff. Thanks a lot in advance!