Can one show me how to plot this graph by hand (composition).
$$\frac{1}{1-x^2}$$
Plot[1/(1 - x^2), {x, -5, 5}]
Output result see picture in the end
Fine, thanks, I got it by plot 1/(1 + x) and 1/(1 - x)
Plot[{1/(1 - x), 1/(1 + x), 1/(1 - x) 1/(1 + x)}, {x, -5, 5}]
Output result see picture in the end


$$\frac{1}{1-x^2}$$ has the domain $\Bbb{R}-\{-1,1\}$
If $x\to\{-1^{+},1^{-}\}$, then $\frac{1}{1-x^2}$ approaches $+\infty$, and if $x\to\{-1^{-},1^{+}\}$, then $\frac{1}{1-x^2}$ approaches $-\infty$
For $x\in(-\infty,-1)\cup (1,\infty)$, $\frac{1}{1-x^2}$ is negative, and tends to $0$ as $x\to\pm\infty$
This should give you some hints as to the general shape of the graph.
For greater accuracy, you may calculate the derivative of the graph at various points.