$$f(x)=\ln^3(x^2+\tan(3x))$$
This is a question from a past final exam. I need to derive this function and I have one simple question. Is it possible for that natural log to have its own exponent. How would I even go about deriving this problem seeing as how $\frac{d}{dx}(\ln(x)) = \frac{1}{x}$ ?
Actually, this can be rewritten as $(\ln(x^2+\tan(3x)))^3$ just like how trig functions like $\sin^2(x)$ are analogous to saying $(\sin(x))^2$