Can we defined a metric so that the non-constant cauchy sequence do not exists, then the space is complete vacuiously

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I know that not all metrics are induced by norm, only those metrics satisfy the homogeneity and translation invariant.

1. Now, Can a normed space equipped with metric not be induced by the norm?

2. If it can, consider this metric if $x\neq y$ $$d(x,y):=\max \{\lVert x-y\rVert_{2},1 \}$$ $$d(x,y):=0\quad x=y$$ with the normed space, my motivation of this metric is bounded below to make sure that there can not have a Cauchy sequence in the space (except for the trivial constant sequence). In such case, is the space vacuously complete by no non-constant Cauchy sequence exists, so that every Cauchy sequence convergence in the space?

Please help me out with these two questions