I'm confused with how to compute the integral in part(a). I know you need to use Cauchy's integral formula, so in part(a) you would have $f(z)=z^3-2z+5$ and $a=1$ which is a point in the interior of $\gamma$, so would you use the formula $f(a)=\frac{1}{2\pi i}\int\frac{f(z)}{z-a} dz$ with $a$ and $f(z)$ defined?