For independent continuous (non-negative) random variables $X$ and $Y$, we may have CDF for $Z=\min(X, Y)$:
\begin{align*} F_Z(t) &= \Pr(X \le t \;\text{or}\; Y \le t) = \Pr(X \le t) + \Pr(Y \le t) - \Pr(X \le t, Y \le t)\\ & = F_X(t) + F_Y(t) - F_X(t) F_Y(t). \end{align*}
However, how can I express the CDF of $Z=\min(X, c)$ when I have a non-negative constant $c$ instead of RV $Y$?
The distribution $\min\{X,c\}$ can be obtained as follows:
$$F_{\min\{X,c\}}(t)=\mathbb P (\min\{X,c\}\le t)=1-\mathbb P (\min\{X,c\}>t)=1-\mathbb P (X>g,c>t)= \begin{cases} F_X(t) & t<c \\ 1 & t\ge c. \end{cases}$$
Note that even if $F_X$ is a continuous distribution, $F_{\min\{X,c\}}$ is a mixed distribution for any $c$ with $0<F_X(c)<1$.
Using the same method for $\min\{X,Y\}$:
$$ F_{\min\{X,Y\}}(t)=1-\mathbb P (\min\{X,Y\}>t)= 1- (1- F_X(t))(1- F_Y(t)).$$
If both $F_X$ and $F_Y$ are continuous distributions, then $\min\{X,Y\}$ also has a continuous distribution.