If I have this integral:
$$\int_0^{\sigma_0}xR^2dR$$
and I know that $x=\frac{R} {\sigma_0}$
and I substitute:
$$\int x (x\sigma_0)^2 dx= \int x^3 \sigma_0^2 dx$$
what are the new integration limits?
If I have this integral:
$$\int_0^{\sigma_0}xR^2dR$$
and I know that $x=\frac{R} {\sigma_0}$
and I substitute:
$$\int x (x\sigma_0)^2 dx= \int x^3 \sigma_0^2 dx$$
what are the new integration limits?
The limits of integration are given as $R= 0$ and $R= \sigma_0$. You change variables from R to $x= \frac{R}{\sigma_0}$. When $R= 0$, then, $x= \frac{0}{\sigma_0}= 0$. When $R= \sigma_0$, $x= \frac{\sigma_0}{\sigma_0}= 1$