change ratio exercise

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A parachutist is launched from an airplane that goes from West to East at $3,000$ m. A child, who at the moment of launching the parachutist is located $500$ m east of the plane (horizontal distance), runs to meet him at a speed of $5$m / s. Assuming that the parachutist falls vertically at a speed of $100$m / s and that the child begins to run at the same moment that the parachutist is released, determine; The distance (diagonal) between the child and the parachutist after 10 s With what speed do they approach each other at that moment ($10$s)?

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HINT

After $10$ seconds

  • the parachutist is at $H=2000$ m of height
  • the chidren is $L=450$ m from the vertical projection of the starting point of the parachutist

then we can use Pythagorean theorem to find $D$.

For the speed let use the same method to find the distance $D(t)$ as a function of the time.