Let $f(x)=\sin|x| ,x \in(-\pi ,\pi)$
Is $f$ continuous in the interval $(-\pi ,\pi)$ ? If it is, then is it differentiable on $(-\pi ,\pi)$ ??
Is it a problem of uniform continuity ? How to solve it?
Let $f(x)=\sin|x| ,x \in(-\pi ,\pi)$
Is $f$ continuous in the interval $(-\pi ,\pi)$ ? If it is, then is it differentiable on $(-\pi ,\pi)$ ??
Is it a problem of uniform continuity ? How to solve it?
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The function $f$ is continuous since $\sin y$ is continuous and $y = |x|$ is continuous. The same argument shows that it is differentiable at least for all $x\neq 0$. Check the case $f'(0)$ by yourself using the definition of the derivative directly.