$x \equiv 1\mod3$
$x \equiv 2\mod 9$
Is it possible to solve this system of congruences?
2026-03-25 09:29:12.1774430952
Chinese Remainder Thoerem - Is it possible to solve a system of congruences that are not coprime?
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$x\equiv 2 \bmod 9\implies x\equiv 2 \bmod 3$
in general $x\equiv a \bmod nk \implies x \equiv a \bmod n$