Clarifying understanding of Poisson Brackets in Hamiltonian Dynamics

85 Views Asked by At

I'm just reading through my textbook and would like to clarify my understanding of 'Canonically related variables'. In my textbook, it says that if $Q_i$, $P_i$ are related to $q_i$, $p_i$ by a canonical transformation then: $$\{Q_j,P_k\} = \delta_{j,k}$$

I'm not exactly sure what $\delta_{j,k}$ refers to, but from what I have gathered - does this refer to the number of degrees of freedom shared by $Q_j$ and $P_k$?

Thanks, just wanted to verify my understanding.

1

There are 1 best solutions below

0
On BEST ANSWER

No, it's just the Kronecker delta: $\delta_{i,j}$ equals $1$ if $i=j$ and $0$ otherwise.