Classifying Singular Points as Regular/Irregular for Differential Equation

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The question asks to find the singular points of the Differential Equation and to classify each of them as regular/irregular:

$x(x^2+1)^2y''+y=0$

Edit: I gave it another shot and I ended up with 3 singular points:

$x=0$ (regular singular point)

$x=+i$ (irregular singular point)

$x=-i$ (irregular singular point)

Could you kindly let me know if I found the correct solution? Thank you for your time.