Since $e=\sum_{n=0}^\infty\frac{1}{n!}=1+1+\frac12(1+\frac13(1+\frac14(1+\dots)))$, we have
$$4^{e-2}=\sqrt{4\cdot\sqrt[3]{4\cdot\sqrt[4]{4\cdots}}}$$
Is there however a nice way to express the radical in the title too?
2026-03-30 08:13:06.1774858386
Closed form expression for $\sqrt{4+\sqrt[3]{4+\sqrt[4]{4+\dots}}}$
513 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in CLOSED-FORM
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