I want to find the closed form of $\begin{align}\int_{0}^{\infty}x^{1-x^{2-x^{3-...}}}dx\end{align}$.
Quick disclaimer: I have no reason to believe one actually exists
Using Desmos, the closest I have gotten is $1.2421832267$.
I have noticed that when it is repeated an odd amount of times, for example $x^{1-x^{2-x^3}}$ the integral does not converge and I would have to change it to $x^{1-x^{|2-x^3|}}$. Is there any way to avoid having to do this (perhaps with a slightly altered equation)? My question is still for the closed form.
I first tried to find the closed form by putting it in Desmos and then plugging the decimal it gave me into WolframAlpha in hopes of getting a closed form but it didn't give me anything, even after I wrote a Python script so I could copy and paste 200 repetitions into Desmos in an attempt to get a more accurate decimal.
Here is my other approach:
The closed form of $\begin{align}\int_{0}^{\infty}x^{1-x^{2-x^{3-...}}}dx\end{align}$ is equal to $\begin{align}\lim_{a\to\infty}\int_{0}^{a}x^{1-x^{2-x^{3-...}}}dx\end{align}$.
This is where I am stuck. Thanks in advance for the help!
I was hoping to provide something for the $\huge \pi$ day.
For an error of $1.33\times 10^{-51}$, the number
$${\large\Xi}=1.2421832266975400643278225490476835939896793761402$$ (obtained using $88$ levels) is such that it could write $$8058940\,{\large\Xi}=-5866165 \binom{\pi }{\pi !}+4785910 \binom{\pi !}{\pi }-14882994 \binom{\pi !}{\log (\pi )}+$$ $$12531710 \binom{\log (\pi )}{\pi !}-14673958 \binom{\pi }{\log (\pi )}-761197 \binom{\log (\pi )}{\pi }$$ which $\cdots\cdots$ does not mean anything.