$1 \leq j \leq n$. Is there a formula that exists to find coefficients for this function? This is as far as i have got it using Sterling numbers of the first kind.. I was wondering if there was a more explicit formula? $$ \prod_{i=1;i \neq j}^{n} (x-i) = \frac{1}{x}\sum_{k=1;k \neq j}^{n+1} \sum_{2 \leq i_1 \leq ... \leq i_{k-1} \leq n+1} \frac{n!}{i_1 ... i_{k-1}}(-1)^{n-k+1}x^k $$
2026-03-29 08:35:44.1774773344
Coefficients of $\prod_{i=1;i \neq j}^{n} (x-i)$
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