The three vectors are coplanar iff they are linearly dependent, and this means that:
$$
\det
\begin{bmatrix}
1&-2&3\\
2&X&-4\\
0&-7&10
\end{bmatrix}
= 0
$$
0
Bumbble Comm
On
Three points $P, Q, R$ are collinear if vectors $PQ$ and $PR$ "point to the same direction". That means $PQ = x * PR$. I suggest to calculate $PQ$ and $PR$ in terms of $a, b, c$ and check if they can "point to the same direction" for some $X$.
The three vectors are coplanar iff they are linearly dependent, and this means that: $$ \det \begin{bmatrix} 1&-2&3\\ 2&X&-4\\ 0&-7&10 \end{bmatrix} = 0 $$