I've been banging my head against the table with this question.
$$ \lim_{x\to a} \frac{x^2 +3x}{x+2} $$ It just doesnt want to simplify
Here's what I have so far for the smaller:
$$ \lim_{x\to a} \frac{-2}{x+2} $$
$$ \frac{2|{x-a}|}{|a+2|}* \frac{1}{|x+2|} $$
So if I bound $$|x-a|<\delta<1$$ can I then say that $$a-1<x<a+1$$ which means that $$\frac{1}{|x+2|} = \frac{1}{|a+1|} or \frac{1}{|a+3|}$$ and then find the min delta with the two of those?
In my class we usually do the triangle inequality so I'm not sure if this works