I need to compute the convolution of these two functions:
$h(t)=\frac{1}{1+e^{-t}},$ $g(t) =e^{-t}p(e^{-t}),$ $t=ln(H)$
I understand how to do it when I ignore the substitution $t=ln(H)$. However, after I substitute $t$ with $ln(H)$, how can I compute the convolution?
When I convolve these two functions, I need to do $h(t-\tau)$ and $g(\tau)$. How does the substitution change this?
Does it become $h(ln(H)-\tau)$ and $g(ln(\tau))$)? or something else?
Thanks so much for help