Computing $\mathbb{P}\left(\left(U + \frac{1}{2}\right)^2 > \frac{1}{2}\right)$ for uniform $U(0,1)$ random variable?

Question

I want to compute $$\mathbb{P}\left(\left(U + \frac{1}{2}\right)^2 > \frac{1}{2}\right)$$ Where $U$ is a $(0,1)$ uniform random variable. My attempt:

$$\mathbb{P}(U + \frac{1}{2} > \frac{1}{\sqrt{2}}) = \mathbb{P}(U > \frac{\sqrt{2} - 1}{2}) = \frac{3 - \sqrt{2}}{2}$$

Is this correct? Any help would be greatly appreciated.

Edit I had a small error in the last step, corrected thanks to comment.