I have the following function $f(k,r)=Ak-r$ where $A>0$ is a constant
Is this function not concave in $(k,r)$? This is just linear. Right?
I have the following function $f(k,r)=Ak-r$ where $A>0$ is a constant
Is this function not concave in $(k,r)$? This is just linear. Right?
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It is linear, but also concave. Linear functions are always concave (and also convex); try verifying this from the definition of concave. However, it is not strictly concave.