Condition for a submanifold of complex Euclidean space to be analytic

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I have seen, but don't fully understand, the following statement and sketch proof:

Statement: A codimension $2$ submanifold $C \subset \mathbb{C}^2$ such that $C$ has positive intersection index with every complex line is complex analytic (i.e. every tangent space is complex).

Sketch Proof: Given a point $p \in C$ we can write $C$ as a graph over it's tangent space $T_pC$ in some neighbourhood of $p$. Now if the tangent space is not complex then one can "easily" find a complex line which has negative intersection index with $C$ at $p$. This is a contradiction and hence $T_pM$ is complex.

My problems are as follows:

1) What exactly is meant by the tangent space not being complex here? 2) How does one find this line precisely?

For the first point if we are considering $C$ as a subset in $\mathbb{C}^2$ then I guess we are talking about the tangent space as a plane in $\mathbb{C}^2$ which would necessarily be complex?

For the second point I guess that if we take a non-complex plane a complex plane both in $\mathbb{C}^2$ then their orientations will be oposite and hence the intersection index will be negative?

Any help will be greatly appreciated!