So i have the sum of the 2 dice rolls with X and that the sum is even/uneven with Y out of 0 or 1
Probabilities: (2=1/36) (3=2/36) (4=3/36) (5=4/36) (6=5/36) (7=6/36) (8=5/36) (9=4/36) (1=3/36) (11=2/36) (12=1/36)
So my problem is to now determine the conditional entropy H(X|Y) and H(Y|X). I just don't get it how to use the formula.
edit: H(X|Y) = Σ p(yj ) * H(X | Y = yj ) and i don't know how to use Pr [X = xi | Y = yj] cause i don't understand the conditional probability. p[x=2|y=0] = 0/(1/2) right? p[x=2|y=1] = (2/32)/(1/2)=4/32. ? So the entropy for that is the Sums of all these entropies?