I need help with solving this one:
"Bowl I contains eight red balls and six blue balls. Bowl II is empty. Four balls are selected at random, without replacement, and transferred from bowl I to bowl II.
One ball is then selected at random from bowl II. Calculate the conditional probability that two red balls and two blue balls were transferred from bowl I to bowl II, given that the ball selected from bowl II is blue"
(The official answer is: 70/143)
Update: Ok, got the answer using p(2,2|blue) = p(blue|2,2)p(2,2) / p(blue). Turned out to be simpler than I had thought.