I had this question in a quiz, and now that I am reviewing it, I am not sure if why my TA gave me the marks because I am pretty sure I am wrong.
Let the r.v. $Y$ follow uniform distribution $U(1,2)$
Find $P(Y > 1.5 | 1.2 < Y < 1.6)$
My attempt:
$\frac{P(Y > 1.5 \cap 1.2 < Y < 1.6)}{P(1.2 < Y < 1.6)}$
$=\frac{P(1.5 < Y < 1.6)}{P(1.2 < Y < 1.6)}$
$=\frac{0.1}{0.4}$
$=\frac{1}{4}$
Have I got it right and my TA is just trying to boost the marks of the class or was my original answer (below) correct:
$=\frac{P(1.2 < Y < 1.6)}{P(Y > 1.5)}$
$=\frac{0.4}{0.5}$
$=\frac{4}{5}$