Lets say we "connect" two numbers in the set of Natural numbers in a way, that we draw an arrow between them. In each step we draw an arrow from a number to the number which is next to it. If we drew an arrow from a number to another we don't draw another one from the number we arrived in the same step.
Example: 1 2 3 4 5 6 7 8 ...
First step: 1->2 3->4 5->6 7->8 ... (since we connected 1 and 2 from 2 draw a line in this step)
Second step 1->2->3->4 5->6->7->8 ... (since we connected 2 and 3 we dont draw a line from 4 in this step)
Third step 1->2->3->4->5->6->7->8 ... (since we connected 4 and 5 we dont draw a line from 8 in this step)
So my question is: If we keep connecting the numbers in this way infinite amount of times, than will they ever connect into one single line or not?
Personally I don't think they ever will, since after every step there will be a number which isn't connected to another number. However if we repeat this infinite amount of times, than that would mean that at some point we reach every number so this way maybe they will connect to a single line. I would really appriciate any help to clarify this.
Yes, all numbers will end up on a single line starting at 1.
We can use induction to prove this.
Inductive Base: It is trivial that $1$ will be on a line starting with $1$
Inductive Step: Suppose $n$ will be on a line starting with $1$. Then if $n+1$ is not already on a line starting with $1$, then an arrow is guaranteed to be drawn between $n$ and $n+1$, since that is the first possible arrow to be drawn given the defined process of drawing arrows. So, if $n$ will be on a line starting with $1$, then $n+1$ will be on a line starting with $1$ as well.