$n$ is natural number.
What is the result of $(-1)^{2n}-(-1)^{4n-1}-1^{n+1}-(-2)^3$
My attempt:
We know that $2n$ means even, and $4n -1$ means an odd number.
Here we get
$$+1 -1 +1+8 = 9$$
Sorry If I was truly wrong, just wanted to show something I did.
It should be just $$1+1-1+8=9.$$
Because $$(-1)^{2n}=\left((-1)^2\right)^n=1^n=1;$$ $$-(-1)^{4n-1}=-(-1)^{-1}\cdot(-1)^{4n}=(-1)^{4n}=\left((-1)^4\right)^n=1^n=1;$$ $$-1^n=-1$$ and $$-(-2)^3=-(-8)=8.$$