I am solving an equation $log_2(1+\frac{xh_d p_d}{s})-\gamma x h_{dc} p_d$
s.t
$xp_d h_{dc}<Q$
my $x$ comes out to be $\frac{1}{\gamma h_{dc} p_d}-\frac{s}{h_d p_d}$
but I dont know how to incorporate the condition $xp_d h_dc<Q$ for $x$ i-e my question is whether my
$x$ = $\frac{1}{\gamma h_{dc} p_d}-\frac{s}{h_d p_d}$ $\quad \quad$ $xp_d h_{dc}<Q$
or
$x=\frac{1}{\gamma h_{dc}^2 p_d^2}-\frac{s}{h_d p_d^2 h_{dc}} \quad\quad xp_d h_dc<Q $ ( i have divided it by $p_d h_{dc})$