Constructing rationals from countable ordinals

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Take the set of all countable ordinals $\omega_1$. Define $+$ and $\cdot$ by the Hessenberg sum and product. In a similar fashion to the naturals, construct the integers and the rationals from these by taking equivalence classes of ordered pairs. We'll call these the "$\omega_1$ rationals". I have a few questions about this construction:

  1. What is the cardinality of the $\omega_1$ rationals? My assumption is that it is $\aleph_1$, as at each step we have only taken pairs of countable ordinals.
  2. Are the $\omega_1$ rationals a field?
  3. Assuming they are a field, what are its properties? Is it metrically complete? Algebraically closed? If it is neither, how far is it from being metrically complete or algebraically closed?
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You're exactly right about the cardinality being $\aleph_1$. This construction does yield a field. To understand it better, note that by Cantor normal form, the semiring $(\omega_1,+,\cdot)$ can be identified with the set of formal polynomials with coefficients in $\mathbb{N}$ in variables $x_\alpha$ for $\alpha<\omega_1$, where $x_\alpha$ corresponds to the ordinal $\omega^{\omega^\alpha}$. So, taking formal differences of such things will just give polynomials in the variables $x_\alpha$ with coefficients in $\mathbb{Z}$, and then taking formal quotients will give rational functions in the variables with coefficients in $\mathbb{Q}$. So this field is a field of rational functions in $\aleph_1$ variables over $\mathbb{Q}$. In particular, it is very far from being algebraically closed (for instance, it contains no elements algebraic over $\mathbb{Q}$ besides the elements of $\mathbb{Q}$ themselves).

(Of course, there is nothing particularly special about $\omega_1$ here. You could do the same thing for any ordinal $\omega^{\omega^\alpha}$, and you would get a field that is a field of rational functions on variables $x_\beta$ corresponding to $\omega^{\omega^\beta}$ for all $\beta<\alpha$.)