This figure is taken from Wolfram MathWorld. The site classified the third region as not simply connected, and I get it, but it isn't also multiply connected, since multiply connected means that I can connect any two points in the region with a curve that lies entirely in the region. However, it is clear that I cant connect one point in the upper subregion with another one in the down subregion with a curve that lies totally in the region, correct?
Note
A multiply connected region is a connected region but not simply.

Often times, a plane region $D$ is simply-connected if
In my experience, one says $D$ is multiply-connected if there exists a closed path in $D$ that is not homotopic in $D$ to a constant path, i.e., given two points of $D$ there exist multiple non-homotopic paths joining them. Offhand I expect (but don't know for certain whether) one normally speaks only of "multiply-connected regions," i.e., not of "multiply-connected (open) sets."
The third set is not connected, hence not simply-connected. Every closed path in $D$ is homotopic in $D$ to a constant path, however, so (using the criterion above, whether or not connectedness is assumed) the third set is also not multiply-connected.