Cosine Function As Infinite Product

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I'm trying to expand cosine function by using the Mittag-Leffler theorem which is introduced in Arfken 7ed.:

$$f(z)=f(0)\exp\left(\frac{zf'(0)}{f(0)}\right)\prod_{n=1}^{\infty}\left(1-\frac{z}{z_n}e^{z/z_n}\right) \tag{11.88}$$

Where $z_n$ is simple point.

First I found $z_n=\frac{2n-1}{2}\pi$.

And the result on the book was

$cosz=\prod_{n=1}^{\infty}(1-\frac{z^2}{(n-1/2)^2\pi^2})$

So I could guess $e^{z/z_n}$ was deformed as $1+\frac{z}{z_n}$.

But if we expand $e^{z/z_n}$, it becomes $1+\frac{z}{z_n}+\frac{1}{2!}(\frac{z}{z_n})^2+\frac{1}{3!}(\frac{z}{z_n})^3+\cdots$

Should I study the gamma function? I didn't study it yet.

I wonder why the higher order disappeared. Can you give me some advice?