Counting cases?

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I don't have a background on probabilities but i do want to get the rule to solve the following problem and similar ones .

Let's say we have a 2x2 matrix , in which every element could be either 1 or 0 . like :

$$\begin{pmatrix} 0& 1 \\ 0& 0 \end{pmatrix} , \begin{pmatrix} 1& 1 \\1& 0 \end{pmatrix} , \begin{pmatrix} 0& 1 \\ 1& 0 \end{pmatrix}\ldots$$

Those were 3 of 16 cases we could get , right ? How do we calculate cases in this kind of problems ? What do we call the study of this kinda probabilities .

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We call this combinatorics. If you search the site for that tag you will find many questions and answers. Generally, if you have several independent choices to make, the total number of options is the product of the number of options at each point. In your example, you have two choices four times, so the total number is $2^4=16$