Suppose we have a sequence of convex multivariate functions
$f_a(\vec{v}): S \to \Bbb R$
defined on some open convex subset $S$ of $\Bbb R^n$, which converge uniformly to some limit function $f_\infty(\vec{v})$.
Question: What criteria exist to establish that $f_\infty(\vec{v})$ is also convex?
I think this question shows this need not be true in general, but is there some simple criterion for when this is true?
FYI, while I have searched and found a lot of questions about uniform convergence and convex functions, I haven't found a question addressing such criteria in the multivariate case. Apologies if this has been asked already.
Pointwise limits of convex functions are convex (by definition) and hence uniform limits too. The post you have referred to is irrelevant to this question.
If $S$ is a convex subset of a vector space $V$ over the reals then a function $f:S \to \mathbb R$ is called convex if $f(tx+(1-t)y) \leq tf(x)+(1-t)f(y)$ whenever $x,y \in S$ and $0 \leq t \leq 1$. If $f_n(tx+(1-t)y) \leq tf_n(x)+(1-t)f_n(y)$ and $f_n \to f$ pointwise to $f$ we can simply let $n \to \infty$ to get $f(tx+(1-t)y) \leq tf(x)+(1-t)f(y)$.