I.e: the vector function $\{t^3, t^2, t\}$ has a curvature of $\dfrac17\sqrt{\dfrac{19}{14}}$, but what happens when you multiply the curvature to something like $3\{t^3, t^2, t\}$? I figure you can just recalculate the curvature at large, but am wondering if this just multiplied the overall curvature by $3$. Thanks!
2026-04-01 09:30:06.1775035806
Curvature multiplied by constant?
111 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in CALCULUS
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