Degree of a single extension of a field.

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Let $K$ be a field. Let $L:=K(b)$ where $b^m\in K$ but $b^i\not\in K$ for all $0<i<m$.

Then is $[L:K]=m$?

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No. For example, $\mathbb{Q}(\zeta_n)/\mathbb{Q}$ has degree $\phi(n)$, but we usually don't have $\zeta_n^{\phi(n)} \in \mathbb{Q}$. For example, when $n=3$, then $\phi(n)=2$, $\zeta_3 = \frac{-1+\sqrt{-3}}{2}$ and $\zeta_3^2 = \frac{-1-\sqrt{-3}}{2}$.