Show that $\lim\frac{x}{y}$ as $(x,y)\to(1,1)$ equals $1$ by the delta epsilon definition.
$\sqrt{(x-1)^2 + (y-1)^2} < \delta$ $|\frac{x}{y}-1| < \epsilon$
How do I proceed?
Show that $\lim\frac{x}{y}$ as $(x,y)\to(1,1)$ equals $1$ by the delta epsilon definition.
$\sqrt{(x-1)^2 + (y-1)^2} < \delta$ $|\frac{x}{y}-1| < \epsilon$
How do I proceed?
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Hint: $\sqrt{(x-1)^2 + (y-1)^2} < \delta$ implies $|x-1|<\delta$ and $|y-1| < \delta$.