I need to determine if the following ring is a field.
$$\mathbb Q[X]/(X^4-2X^2+8X+1)$$ I assume I need to show that it is commutative, has a multiplicative identity and that every non zero element is has a multiplicative inverse, but I am unsure how to go about this.
It suffices to show that the polynomial $f(x)=x^4-2x^2+8x+1$ is irreducible.
(Because $\mathbb{Q}$ is a field, hence $\mathbb{Q}[x]$ is a P.I.D. and hence every prime ideal is maximal...)
First notice that if the polynomial has roots in $\mathbb{Q}$ it would be $1,-1$(Rational root theorem). So the polynomial $f(x)$ have no rational roots.
Now it is enough to check if it's irreducible in $\mathbb{Z}[x]$ (Gauss lemma).
Hence if it's not irreducible it's must be the product of two polynomials of $\mathbb{Z}[x]$ with degree 2.
Assume that this is true, and take
$x^4-2x^2+8x+1= (a_1x^2+b_1x+c_1)(a_2x^2+b_2x+c_2)$
Solve the system and you'll have a contradiction!
There are a few faster ways to do this, but this is a standard way!