There is a quadratic function $(x+1) (x-3)$.
Determine the value of the square root of 3 by drawing a suitable straight line
I have got no thought here hence there are no workings.
Any help here would be highly appreciated:)
2026-04-03 14:07:24.1775225244
Determine square root of 3 by drawing a straight line
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Observe that $x = \sqrt 3$ satisfies the equation $$f(x) = -2x$$ Here, $f(x) = x^2 - 2x -3 $
Now, If we were to draw the line $y=-2x$, and find it's point of intersection with our given curve, we would then drop the perpendicular from that point to $x$ axis. This would give us the value of $\sqrt 3$