Determine whether the following are uniformly continuous
(a) $ x \rightarrow x^3, x\in \mathbb{R} $ and (b) $ x \rightarrow x^3, x\in [0,1] $.
I just don't get these, I figured that (b) is and (a) isn't but I have no idea how to prove them.
Determine whether the following are uniformly continuous
(a) $ x \rightarrow x^3, x\in \mathbb{R} $ and (b) $ x \rightarrow x^3, x\in [0,1] $.
I just don't get these, I figured that (b) is and (a) isn't but I have no idea how to prove them.
For $a) $, consider
$$u_n=n$$ and $$v_n=n+\frac 1 n$$ we have
$$\lim_{n\to+\infty}(v_n-u_n)=0$$ but $$\lim_{n\to+\infty}(v_n^3-u_n^3)=+\infty\ne 0$$
thus $x \mapsto x^3$ is not uniformly continuous at $\mathbb R $.
$$x^3-y^3=(x-y)(x^2+xy+y^2) $$ with $0\le x\le1$ and $0\le y\le 1$, thus $$|x^3-y^3|\le 3|x-y|$$
then to satisfy $|x^3-y^3|<\epsilon $, take $\eta=\frac {\epsilon}{3} $.