This came from a silly hypothetical question. How many Seans would it take to contain the Earth inside a Spherical Polyhedron made of 3-Sean triangles*.
I think I have enough information to solve it:
- Our edge length is 1.98 meters (Sean is 6' 6" tall)
- Our minimum diameter is 12742000 meters (equatorial earth diameter)
But I'm not sure how to go about solving it.
*Not triangles technically, but you know what I mean
EDIT: Here's what I'm thinking...
- Surface area of the earth is ~510000000000000 m^2
- Area of Sean-Triangle (1.98m Equilateral) is 1.7m^2
- Therefore ~300000000000000 Sean-Triangles
To use Euler's Polyhedron formula I would need to know the number of vertices, and then I could determine the number of edges.