I am trying to calculate probability in a dice rolling scenario.
Specifically, when I throw 12 dice, and I want to get at least 5 equal pairs.
That is, either:
1,1 2,2 3,3 4,4 5,5
Or
1,1 2,2 3,3 4,4 6,6
Or
1,1 2,2 3,3 5,5 6,6
…
I want to find out the P of the above, by having 2 chances.
With “by having 2 chances” I mean: you throw the dice, and you are able to leave any pairs you have… That is, if you get among the 12 dice 3,3 and 4,4 and 5,5 you keep those and throw again the remaining 6 dice.
(Whenever I google this, “2 chances” means that you throw all the dices in each chance, which is not what I am looking for)