$\dim R$=$\sup\{\dim R_f|f\in R\}$

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we wrote in a comment in our script the following:

If $R$ is a ring: $\dim R=\sup\{\dim R_f\mid f\in R\}$.

We defined: $R_f:=(\{f^n|n\in\mathbb{N}\})^{-1}R$

We didn't prove this. Should this be obvious? Can someone explain why this is true? Thanks in advance.