Distance between two objects given their angle of depression

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A boat is situated between a lighthouse and a ship such that all three of them are in a straight line. If the angles of depression of the boat and the ship from the top of the lighthouse $20$ meters above sea level are $30$ degrees and $15$ degrees respectively. What is the distance between the boat and ship?

I did $20\tan(75^\circ) - 20\tan(60^\circ)$ which gave me $40$ meters and I am not sure if it's correct since the instructions said round your answer in hundredths.