I know that
harmonic mean HM <= geometric mean GM <= arithmetic mean AM
Thus, if I have two groups of observations such that
AM of group 2 > AM of group 1
The smallest possible value of an observation is 1.
Is is true that the same inequality holds for the other two types of means:
GM of group 2 > GM of group 1 HM of group 2 > HM of group 1
Many thanks,
Simone
Absolutely no. You will still have $HM\leqslant GM\leqslant AM$ within each group, but that's about it.
Say, our groups are $\{20,20\}$ and $\{5,45\}$. Then $\stackrel{\color{red}{20}}{AM_1}\;<\;\stackrel{\color{red}{25}}{AM_2}$, but $\stackrel{\color{red}{20}}{GM_1}\;>\;\stackrel{\color{red}{15}}{GM_2}$ and $\stackrel{\color{red}{20}}{HM_1}\;>\;\stackrel{\color{red}{9}}{HM_2}$.