Suppose $A$ is positive definite, such that for all $x \in \mathbb{R}^n$, we have:
$$x^TAx > 0$$
Do we say $A$ is positive definite on $\mathbb{R}^n$ or $\mathbb{R}^n \times \mathbb{R}^n$
Suppose $A$ is positive definite, such that for all $x \in \mathbb{R}^n$, we have:
$$x^TAx > 0$$
Do we say $A$ is positive definite on $\mathbb{R}^n$ or $\mathbb{R}^n \times \mathbb{R}^n$
Remember that $x^T$ is the transpose of the vector $x$, so ultimately, the input is just one vector in $\mathbb{R}^n$. Think about the quadratic form as $q(x) = \langle Ax,x\rangle$.