Does minimizing the action for a lagrangian also minimize the action for the square of the lagrangian?

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Let's say I have found the path for which the action:

$$ S = \int_{x_1}^{x_2}\mathcal{L}(y(x),y'(x),x) dx $$

Is minimized. Does this mean that this path minimizes the integral of the square of the Lagrangian? I have started sketching a proof by considering the variation of the integral of $\mathcal{L}^2$, but have hit a wall trying to integrate by parts. If this does not hold in general, are there conditions on $\mathcal{L}$ for which this is true?