Does order matter in the epsilon-delta definition?

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Are the following statements equivalent?

Statement 1

For any $\epsilon>0$, there exists $\delta>0$ such that for all real number $x$, if $|x-x_0|<\delta$, then $|f(x)-f(x_0)|<\epsilon$

Statement 2

There exists $\delta>0$ such that for any $\epsilon>0$, for all real number $x$, if $|x-x_0|<\delta$, then $|f(x)-f(x₀)|<\epsilon$

If so, can the second statement also be used as a definition for limits?