Does screw decomposition mean that order of rotation and translation does't matter in 3D Euclidean transformation?

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This problem comes from R.Hartley & A.Zisserman Multiple View Geometry in Computer Vision at page 78, the Result 3.6 says

Any particular translation and rotation is equivalent to a rotation about a screw axis together with a translation along the screw axis. The screw axis is parallel to the rotation axis.

To my understanding, order of rotation and translation will make a difference on Euclidean translation. because $$Rx+t \neq R(x+t)$$ Now decompose translation into $t_{\bot}$ and $t_{||}$, and do screw decomposition as follows:enter image description here

So whether or not it doesn't matter when exchange the order of translating $t_{||}$ along $\mathbf a$ and rotating about $\mathbf a$?