Does the natural number $N$ determine an upper limit of $2^m$ that can be reached with the Collatz conjecture?

77 Views Asked by At

I have just recently learned about the Collatz conjecture and have been researching it for fun.

For this question, $m$ and $N$ are natural numbers.

I am interested in $2^m$ that the natural number $N$ can reach by the Collatz Conjecture, so I am looking it up. Then I found A054646 in oeis.

This is a list of the smallest natural numbers that can reach $2^m$ by the Collatz Conjecture.

This sequence is monotonically increasing as far as it is currently computed.

This surprised me because my intuition was that the $2^m$ that could be reached for a natural number $N$ was random.

If this sequence is still monotonically increasing after this, then there is an upper limit of $2^m$ that can be reached for the natural number $N$.

Please let me know if you have any information for this sequence.


Concrete examples

$\frac{4^n-1}{3}$ is the odd number just before reaching $2^m$ ($n$ is natural number).

The ratio of $\frac{4^n-1}{3}$ to $A054646(n)$ is currently less than 4.

I suspect this is because there is an upper limit of $2^m$ that the natural number $N$ can reach.

$\frac{4^n-1}{3}$ $A054646(n)$ $\frac{4^n-1}{3} / A054646(n)$
1 1 1.0
5 3 1.6666666666666667
21 21 1.0
85 75 1.1333333333333333
341 151 2.2582781456953644
1365 1365 1.0
5461 5461 1.0
21845 14563 1.500034333585113
87381 87381 1.0
349525 184111 1.8984471324364107
1398101 932067 1.5000005364421227
5592405 5592405 1.0
22369621 13256071 1.6875000895815961
89478485 26512143 3.375000089581593
357913941 357913941 1.0
1431655765 1431655765 1.0
5726623061 3817748707 1.5000000001309672
22906492245 22906492245 1.0
91625968981 91625968981 1.0
366503875925 244335917283 1.5000000000020464
1466015503701 1466015503701 1.0
5864062014805 5212499568715 1.12500000000012
23456248059221 10424999137431 2.25000000000012
93824992236885 93824992236885 1.0

More concrete examples

The Collatz sequence for the natural number $7$ is as follows.

$$ 7 \rightarrow 22 \rightarrow 11 \rightarrow 34 \rightarrow 17 \rightarrow 52 \rightarrow 26 \rightarrow 13 \rightarrow 40 \rightarrow 20 \rightarrow 10 \rightarrow 5 \rightarrow 16 \rightarrow 8 \rightarrow 4 \rightarrow 2 \rightarrow 1$$

My expectation in this question is that the reason why large powers of $2$, e.g., $2^{10}$, do not appear in this sequence is because $N$ is as small as $7$.