If $A$ and $B$ are two invertible $5 \times 5$ matrices, does $B^{T}A$ remain invertible?
I cannot find out is there any properties of invertible matrix to my question.
Thank you!
If $A$ and $B$ are two invertible $5 \times 5$ matrices, does $B^{T}A$ remain invertible?
I cannot find out is there any properties of invertible matrix to my question.
Thank you!
Of course: $B$ invertible implies $B^T$ invertible, and the product of two invertible matrices is clearly invertible.
This is easily seen from these equations: $$BB^{-1}=I\implies (BB^{-1})^T=I\implies (B^{-1})^TB^T=1,$$ and the fact that if $X$ and $Y$ are invertible, $(XY)^{-1}=Y^{-1}X^{-1}$.
Perhaps the general properties you should take away are these:
$(XY)^T=Y^TX^T$ and $(XY)^{-1}=Y^{-1}X^{-1}$.