Two coins are tossed once, where E: tail appears on one coin, F: one coin shows head. The event 'F' refers that it had happened already. The question is what is the probability of finding one tail —the event 'E' happening— from one of two coins if already one coin showing up heads, mathematical statement goes as P(E|F).
2026-05-05 23:08:57.1778022537
Does the tail got a 50-50 chance of appearing itself if one of two coins already identifies itself as heads
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In this case it is relevant if you toss two coins at the same time or if you toss the same coin twice.
If you toss the same coin twice the probability of a head in the second try is $\frac 12$ because it is independet from the first try.
But if you have two coins and toss them at the same time and then only look at one coin at first the situation changes. There are four possible outcomes for the two coins: $\{ hh,ht,th,tt\}$ each of them having a probability of $\frac 14$. When we already know that on coin shows head, only three of these possibilities are left, namely $hh,ht,th$. Out of these three (equally probable) possible outcomes two contain atleast one tail - therefore the probability for a tail appearing when we know that one head appeared is $\frac 23$.